Radius of earth 6400 km.
Time period of a satellite revolving earth is given as t height at which it orbits the earth.
This gives the height of a satellite above the earth s surface whose time period is same as that of earth s.
Then r gm e t 2 4π 2 1 3 42400 km and h 36000 km.
The speed of the satellite is 7 519 km s and the period of revolution of the satellite is 5930 s.
What is the time period of a satellite orbiting at a height of 2 5 r above the earth s surface.
G 9 8 m s 2.
Such a satellite appears to be stationary when observed from the earth s surface and is hence known as geostationary satellite.
The period of the earth as it travels around the sun is one year.
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If you know the satellite s speed and the radius at which it orbits you can figure out its period.
If time period of a satellite is 24 hrs.
The time period of an earth stellite in circuarl orbit is independet fo.
The mean angular velocity of the earth around the sun is 1 per day.
Where r is the radius of the earth.
A satellite at this height takes 12 hours to complete an orbit.
Two medium earth orbits are notable.
Radius of earth r 6400 km 6 4 x 10 8 m radius of orbit of moon r 3 84 x 10 5.
T 5071 3600 1 408 h.
The semi synchronous orbit is a near circular orbit low eccentricity 26 560 kilometers from the center of the earth about 20 200 kilometers above the surface.
The speed of the satellite is 7 931 km s and the time of revolution of the satellite is 1 408 h.
In this case you add the distance from the center of the earth to the surface of the earth 6 38 10 6 meters to the satellite s height above the earth.
The semi synchronous orbit and the molniya orbit.
R 1 r 6r 7r r 2 r 2 5 r 3 5 r time period of geostationary satellite t 1 24 hours.
The time period of a satellite orbiting around the earth is given by.
A geostationary satellite is orbiting the earth at a height of 6r above its surface.
You can calculate the speed of a satellite around an object using the equation.
Neither the mass of the satellite nor the radius of it orbits.
Now if the height of the satellite h from the surface of the earth is negligible with respect to the radius of the earth then we can write r r h r as h is negligible.
Distance of moon from the earth 3 84 x 10 5 km.
T 2πr v c 2 x 3 142 x 6400 7 931 5071 s.
From the following data calculate the period of revolution of the moon around the earth.
The time period of an earth stellite in circuarl orbit is independet fo.
